0=-4.9x^2+16x+1.4

Solution for 0=-4.9x^2+16x+1.4 equation:

0=-4.9x^2+16x+1.4

We move all terms to the left:

0-(-4.9x^2+16x+1.4)=0

We add all the numbers together, and all the variables

-(-4.9x^2+16x+1.4)=0

We get rid of parentheses

4.9x^2-16x-1.4=0

a = 4.9; b = -16; c = -1.4;
Δ = b2-4ac
Δ = -162-4·4.9·(-1.4)
Δ = 283.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-\sqrt{283.44}}{2*4.9}=\frac{16-\sqrt{283.44}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+\sqrt{283.44}}{2*4.9}=\frac{16+\sqrt{283.44}}{9.8}
$